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9x^2-24=-6x
We move all terms to the left:
9x^2-24-(-6x)=0
We get rid of parentheses
9x^2+6x-24=0
a = 9; b = 6; c = -24;
Δ = b2-4ac
Δ = 62-4·9·(-24)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-30}{2*9}=\frac{-36}{18} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+30}{2*9}=\frac{24}{18} =1+1/3 $
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